/***
*memcpy - Copy source buffer to destination buffer
*
*Purpose:
* memcpy() copies a source memory buffer to a destination memory buffer.
* This routine does NOT recognize overlapping buffers, and thus can lead
* to propogation.
*
* For cases where propogation must be avoided, memmove() must be used.
*
*Entry:
* void *dst = pointer to destination buffer
* const void *src = pointer to source buffer
* size_t count = number of bytes to copy
*
*Exit:
* Returns a pointer to the destination buffer
*
*Exceptions:
*******************************************************************************/
void * __cdecl memcpy (
void * dst,
const void * src,
size_t count
)
{
void * ret = dst;
/*
* copy from lower addresses to higher addresses
*/
while (count--) {
*(char *)dst = *(char *)src;
dst = (char *)dst + 1;
src = (char *)src + 1;
}
return(ret);
}