很简单的题。直接按照题意模拟即可。
/**//*************************************************************************
Author: WHU_GCC
Created Time: 2000-9-10 16:23:49
File Name: pku1473.cpp
Description:
************************************************************************/
#include <iostream>
#include <cmath>
using namespace std;
#define out(x) (cout << #x << ": " << x << endl)
typedef long long int64;
const int maxint = 0x7FFFFFFF;
const int64 maxint64 = 0x7FFFFFFFFFFFFFFFLL;
template <class T> void show(T a, int n) 
{ for (int i = 0; i < n; ++i) cout << a[i] << ' '; cout << endl; }
template <class T> void show(T a, int r, int l) { for (int i = 0; i < r; ++i) show(a[i], l); cout << endl; }
const double dx[] = {0, 1, 1, 1, 0, -1, -1, -1};
const double dy[] = {1, 1, 0, -1, -1, -1, 0, 1};
const double inv_sqrt2 = 1.0 / sqrt(2.0);
const double p[] = {1, inv_sqrt2, 1, inv_sqrt2, 1, inv_sqrt2, 1, inv_sqrt2};
const char name[8][5] = {"N", "NE", "E", "SE", "S", "SW", "W", "NW"};
int main()
{
double x = 0.0, y = 0.0;
int ca = 1;
while (1)
{
char s[100];
scanf("%[0-9NEWSD]", s);
if (strcmp(s, "END") == 0)
break;
char ch;
scanf("%c", &ch);
double len = 0;
int i;
for (i = 0; s[i] >= '0' && s[i] <= '9'; i++)
len = len * 10 + (s[i] - '0');
for (int j = 0; j < 8; j++)
if (strcmp(s + i, name[j]) == 0)
{
x += len * dx[j] * p[j];
y += len * dy[j] * p[j];
}
if (ch == '.')
{
printf("Map #%d\n", ca++);
printf("The treasure is located at (%.3lf,%.3lf).\n", x, y);
printf("The distance to the treasure is %.3lf.\n\n", sqrt(x * x + y * y));
x = y = 0.0;
scanf("\n");
}
}
return 0;
}