Posted on 2009-08-27 16:41
Uriel 阅读(487)
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POJ 、
DP
这题丢了几天。。没想到是0-1背包。。。
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/**//*Problem: 3628 User: Uriel
Memory: 9228K Time: 110MS
Language: C++ Result: Accepted*/
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#include<stdio.h>
#include<stdlib.h>
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int N,B,H[21],i,dp[21][20000002],j,sum,k;
int main()
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{
scanf("%d %d",&N,&B);
sum=0;
for(i=1;i<=N;i++)
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{
scanf("%d",&H[i]);
sum+=H[i];
}
for(j=N;j>=0;j--)
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{
dp[j][0]=1;
}
for(i=1;i<=N;i++)
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{
for(j=sum;j>=H[i];j--)
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{
for(k=0;k<i;k++)
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{
if(dp[k][j-H[i]]==1)
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{
dp[i][j]=1;
}
}
}
}
for(i=B;i<=sum;i++)
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{
for(j=1;j<=N;j++)
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{
if(dp[j][i]==1)
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{
printf("%d\n",i-B);
goto flag;
}
}
}
flag:system("PAUSE");
return 0;
}
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