并查集的一个应用,地址: http://acm.pku.edu.cn/JudgeOnline/problem?id=1984
//并查集合的一个应用

#include <stdio.h>
#include <math.h>

int p[40005];

typedef struct
  {
int x;
int y;
}point;
point dis[40005];

void make ( int n )
  {

for ( int i=0; i<n; i++ )
 {
p[i] = -1;
dis[i].x = dis[i].y = 0;
}
}

int find ( int pre )
  {

if ( p[pre] < 0 )
 {
return pre;
}
int root = find ( p[pre] );

dis[pre].x += dis[ p[pre] ].x;
dis[pre].y += dis[ p[pre] ].y;

p[pre] = root;

return root;
}

void un ( int a, int b, int l, char done )
  {

int ra = find ( a );
int rb = find ( b );
point oldp, newp;
oldp.x = dis[b].x;
oldp.y = dis[b].y;

if ( done == 'E' )
 {
newp.x = dis[a].x + l;
newp.y = dis[a].y;
}
else if ( done == 'S' )
 {
newp.x = dis[a].x;
newp.y = dis[a].y - l;
}
else if ( done == 'W' )
 {
newp.x = dis[a].x - l;
newp.y = dis[a].y;
}
else
 {
newp.x = dis[a].x;
newp.y = dis[a].y + l;
}

p[rb] = ra;
dis[rb].x = newp.x - oldp.x;
dis[rb].y = newp.y - oldp.y;
}

struct
  {
int a;
int b;
int l;
char done;
}rela[40005];

struct
  {
int next;
int last;
}head[40005];

struct
  {
int a;
int b;
int addr;
int i;
int next;
}po[10005];
int now;

void inith ( int n )
  {

now = 0;
for ( int i=0; i<n; i++ )
 {
head[i].next = head[i].last = -1;
}
}

void add ( int a, int b, int i, int addr )
  {

po[now].a = a;
po[now].b = b;
po[now].addr = addr;
po[now].next = -1;

if ( head[i].next == -1 )
 {
head[i].next = now;
}
else
 {
po[ head[i].last ].next = now;
}
head[i].last = now ++;
}

int que[10005];

int main ()
  {

int n, m;
int a, b, l;
char in[5];
int k;
int f1, f2, di;

while ( scanf ( "%d%d", &n, &m ) != EOF )
 {
for ( int i=0; i<m; i++ )
 {
scanf ( "%d%d%d%s", &a, &b, &l, in );
rela[i].a = a-1;
rela[i].b = b-1;
rela[i].l = l;
rela[i].done = in[0];
}
make ( n );
inith ( m );
scanf ( "%d", &k );
for ( i=0; i<k; i++ )
 {
scanf ( "%d%d%d", &f1, &f2, &di );
add ( f1-1, f2-1, di-1, i );
}
for ( i=0; i<m; i++ )
 {
if ( find ( rela[i].a ) != find ( rela[i].b ) )
 {
un ( rela[i].a, rela[i].b, rela[i].l, rela[i].done );
}
for ( int j=head[i].next; j!=-1; j=po[j].next )
 {
if ( find ( po[j].a ) != find ( po[j].b ) )
 {
que[po[j].addr] = -1;
}
else
 {
int ans = abs ( dis[ po[j].a ].x - dis[ po[j].b ].x ) + abs ( dis[ po[j].a ].y - dis[ po[j].b ].y );
que[po[j].addr] = ans;
}
}
}
for ( i=0; i<k; i++ )
 {
printf ( "%d\n", que[i] );
}
}
return 0;
}

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