大数的运算,地址: http://acm.pku.edu.cn/JudgeOnline/problem?id=2325
#include<stdio.h> #include<stdlib.h> #include<string.h> const int OneNode = 1000000; //??????????????OneNode const int NodeLen = 6; //????????NodeLen??????OneNode????????????,????????????????????????!!! const int NumMax = 1005; //????????????????????????NumMax*6 struct BigNum { unsigned num[NumMax] ;//???? ?? ???????? unsigned numlen ; void set(unsigned sm=0){ num[0] = sm ; numlen = 1; }//sm<OneNode void set(char *string , int strlen) { numlen = (strlen-1) / NodeLen + 1 ; memset (num , 0 , sizeof(unsigned)*numlen ); int temp , i ; for( i=strlen-1 ; i>=0 ; i-- ) { temp = i / NodeLen ; num[temp] = num[temp]*10 + string[strlen-1-i]-'0' ; } } void print() { printf("%d",num[numlen-1]); int i = numlen-1; while( i ) { i--; printf("%06d",num[i]); } printf("\n"); } };
int Cmp(BigNum &a,BigNum &b) //a>b --> 1 , > --> -1 ,== --> 0 { if( a.numlen>b.numlen ) return 1; if( a.numlen<b.numlen ) return -1; int len = a.numlen ; while(len) { len --; if(a.num[len]>b.num[len])return 1; if(a.num[len]<b.num[len])return -1; } return 0; }
void Cpy(BigNum &a , BigNum &b) //b-->a { a.numlen=b.numlen; memcpy(a.num,b.num,sizeof(unsigned)*b.numlen); }
void Div(BigNum &a,int b,int &l) // a/=b -> ????l { int carry=0; int i; for(i=a.numlen-1;i>=0;i--) { a.num[i]+=carry*OneNode; carry=a.num[i]%b; a.num[i]/=b; } if(a.numlen>1&&!a.num[a.numlen-1])a.numlen--; l=carry; }
int dig[9] = {1,2,3,4,5,6,7,8,9};
BigNum a, b, c;
char input[1005];
int ans[1005];
int main() {
int i; int p; int l; int flag; while (1) { scanf("%s", &input); if (input[0]=='-') { break; } a.set(input, strlen(input)); c.set("10", 2); if (Cmp(a, c)<0) { printf("1"); a.print(); } else { p = -1; flag = 0; while (Cmp(a, c)>=0) { for (i=8; i>0; i--) { Cpy(b, a); Div(b, dig[i], l); if (l==0) { flag = 1; ans[++p] = dig[i]; Cpy(a, b); break; } } if (!flag) { p = -1; break; } else { flag = 0; } } if (Cmp(a, c)<0) { for (i=8; i>=0; i--) { Cpy(b, a); Div(b, dig[i], l); if (l==0) { ans[++p] = dig[i]; break; } } } if (p!=-1) { for (i=p; i>=0; i--) { printf("%d", ans[i]); } printf("\n"); } else { printf("There is no such number.\n"); } } } return 0; }
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