技术,瞎侃,健康,休闲……

mahu@cppblog 人类的全部才能无非是时间和耐心的混合物
posts - 11, comments - 13, trackbacks - 0, articles - 12
  C++博客 :: 首页 :: 新随笔 :: 联系 :: 聚合  :: 管理

Booklet Printing

Posted on 2006-06-16 23:26 mahudu@cppblog 阅读(418) 评论(0)  编辑 收藏 引用 所属分类: C/C++
   

When printing out a document, normally the first page is printed first, then the second, then the third, and so on until the end. However, when creating a fold-over booklet, the order of printing must be altered. A fold-over booklet has four pages per sheet, with two on the front and two on the back. When you stack all the sheets in order, then fold the booklet in half, the pages appear in the correct order as in a regular book.

For example, a 4-page booklet would print on 1 sheet of paper: the front will contain page 4 then page 1, and the back will contain page 2 then page 3.

                       Front              Back
------------- -------------
| | | | | |
| 4 | 1 | | 2 | 3 |
| | | | | |
------------- -------------

Your task is to write a program that takes as input the number of pages to be printed, then generates the printing order.

Input 

The input file contains one or more test cases, followed by a line containing the number 0 that indicates the end of the file.

Each test case consists of a positive integer n on a line by itself, where n is the number of pages to be printed; n will not exceed 100.

Output 

For each test case, output a report indicating which pages should be printed on each sheet, exactly as shown in the example. If the desired number of pages does not completely fill up a sheet, then print the word Blank in place of a number. If the front or back of a sheet is entirely blank, do not generate output for that side of the sheet.

Output must be in ascending order by sheet, front first, then back.

Sample Input 

1
14
4
0

Sample Output 

Printing order for 1 pages:
Sheet 1, front: Blank, 1
Printing order for 14 pages:
Sheet 1, front: Blank, 1
Sheet 1, back : 2, Blank
Sheet 2, front: 14, 3
Sheet 2, back : 4, 13
Sheet 3, front: 12, 5
Sheet 3, back : 6, 11
Sheet 4, front: 10, 7
Sheet 4, back : 8, 9
Printing order for 4 pages:
Sheet 1, front: 4, 1
Sheet 1, back : 2, 3

Solution

#include <iostream>
using namespace std;
#define PAGES 100

typedef 
struct side{    
    
int left,right;
}
side;

typedef 
struct sheet{
    side front;
    side back;    
}
sheet;

int numSides;
sheet sheets[PAGES];

void PrintPages(int numSides){
    
int numSidesNew;    
    
int add,pages;
    add 
= numSides%4;
    
if(add != 0){
        numSidesNew 
= numSides + 4 - add;    // 增加后的总面数,numSides为实际的总面数
    }

    
else
        numSidesNew 
= numSides;
    pages 
= numSidesNew / 4;    // 总纸张数
    for(int i = 0; i < pages; i++){
        sheets[i].front.left 
= numSidesNew - 2*i;
        
if(sheets[i].front.left > numSides){
            sheets[i].front.left 
= 0;    // 表明应为blank
        }

        sheets[i].front.right 
= 2*i+1;
        
if(sheets[i].front.right > numSides){
            sheets[i].front.right 
= 0;    // 表明应为blank
        }

        sheets[i].back.left 
= 2*(i+1);
        
if(sheets[i].back.left > numSides){
            sheets[i].back.left 
= 0;    // 表明应为blank
        }

        sheets[i].back.right 
= numSidesNew - 2*- 1;
        
if(sheets[i].back.right > numSides){
            sheets[i].back.right 
= 0;
        }

    }


    cout 
<< "Printing order for " << numSides << " pages:" << endl;
    
for(int j = 0; j < pages; j++){
        
if(sheets[j].front.left || sheets[j].front.right){
            cout 
<< "Sheet " << j+1 <<", front: ";
            
if(sheets[j].front.left)
                cout 
<< sheets[j].front.left << ",";
            
else
                cout 
<< "Blank,";
            cout 
<< " ";
            
if(sheets[j].front.right)
                cout 
<< sheets[j].front.right;
            
else
                cout 
<< "Blank,";
            cout 
<< endl;
        }

        
if(sheets[j].back.left || sheets[j].back.right){
            cout 
<< "Sheet " << j+1 <<", back : ";
            
if(sheets[j].back.left)
                cout 
<< sheets[j].back.left << ",";
            
else
                cout 
<< "Blank,";
            cout 
<< " ";
            
if(sheets[j].back.right)
                cout 
<< sheets[j].back.right;
            
else
                cout 
<< "Blank";
            cout 
<< endl;
        }


    }

}



int main()
{
    
int numSides;
    
while(cin >> numSides){
        
if(numSides == 0){
            
break;
        }

        PrintPages(numSides);
    }

    
return 0;
}


只有注册用户登录后才能发表评论。
网站导航: 博客园   IT新闻   BlogJava   知识库   博问   管理