Preamble: what is a reference type?
In .NET (and therefore C#) there are two main sorts of type: reference types and value types. They act differently, and a lot of confusion about parameter passing is really down to people not properly understanding the difference between them. Here's a quick explanation:
A reference type is a type which has as its value a reference to the appropriate data rather than the data itself. For instance, consider the following code:
StringBuilder sb = new StringBuilder();
(I have used StringBuilder as a random example of a reference type - there's nothing special about it.) Here, we declare a variable sb, create a new StringBuilder object, and assign to sb a reference to the object. The value of sb is not the object itself, it's the reference. Assignment involving reference types is simple - the value which is assigned is the value of the expression/variable - i.e. the reference. This is demonstrated further in this example:
StringBuilder first = new StringBuilder();
StringBuilder second = first;
Here we declare a variable first, create a new StringBuilder object, and assign to first a reference to the object. We then assign to second the value of first. This means that they both refer to the same object. They are still, however, independent variables themselves. Changing the value of first will not change the value of second - although while their values are still references to the same object, any changes made to the object through the first variable will be visible through the second variable. Here's a demonstration of that:
StringBuilder first = new StringBuilder();
StringBuilder second = first;
first.Append ("hello");
first = null;
Console.WriteLine (second);
Output:
Here, we declare a variable first, create a new StringBuilder object, and assign to first a reference to the object. We then assign to second the value of first. We then call the Append method on this object via the reference held in the first variable. After this, we set the first variable to null (a value which doesn't refer to any object). Finally, we print out the results of calling the ToString method on the StringBuilder object via the reference held in the second variable. hello is displayed, demonstrating that even though the value of first has changed, the data within the object it used to refer to hasn't - and second still refers to that object.
Class types, interface types, delegate types and array types are all reference types.
Further preamble: what is a value type?
While reference types have a layer of indirection between the variable and the real data, value types don't. Variables of a value type directly contain the data. Assignment of a value type involves the actual data being copied. Take a simple struct, for example:
public struct IntHolder
{
public int i;
}
Wherever there is a variable of type IntHolder, the value of that variable contains all the data - in this case, the single integer value. An assignment copies the value, as demonstrated here:
IntHolder first = new IntHolder();
first.i=5;
IntHolder second = first;
first.i=6;
Console.WriteLine (second.i);
Output:
Here, second.i has the value 5, because that's the value first.i has when the assignment second=first occurs - the values in second are independent of the values in first apart from when the assignment takes place.
Simple types (such as float, int, char), enum types and struct types are all value types.
Note that many types (such as string appear in some ways to be value types, but in fact are reference types. These are known as immutable types. This means that once an instance has been constructed, it can't be changed. This allows a reference type to act similarly to a value type in some ways - in particular, if you hold a reference to an immutable object, you can feel comfortable in returning it from a method or passing it to another method, safe in the knowledge that it won't be changed behind your back. This is why, for instance, the string.Replace doesn't change the string it is called on, but returns a new instance with the new string data in - if the original string were changed, any other variables holding a reference to the string would see the change, which is very rarely what is desired.
Constrast this with a mutable (changeable) type such as ArrayList - if a method returns the ArrayList reference stored in an instance variable, the calling code could then add items to the list without the instance having any say about it, which is usually a problem. Having said that immutable reference types act like value types, they are not value types, and shouldn't be thought of as actually being value types.
For more information about value types, reference types, and where the data for each is stored in memory, please see my other article about the subject.
Value Parameters
There are four different kinds of parameters in C#: value parameters (the default), reference parameters (which use the ref modifier), output parameters (which use the out modifier), and parameter arrays (which use the params modifier). You can use any of them with both value and reference types. When you hear the words "reference" or "value" used (or use them yourself) you should be very clear in your own mind whether you mean that a parameter is a reference or value parameter, or whether you mean that the type involved is a reference or value type. If you can keep the two ideas separated, they're very simple.
By default, parameters are value parameters. This means that a new storage location is created for the variable in the function member declaration, and it starts off with the value that you specify in the function member invocation. If you change that value, that doesn't alter any variables involved in the invocation. For instance, if we have:
void Foo (StringBuilder x)
{
x = null;
}
...
StringBuilder y = new StringBuilder();
y.Append ("hello");
Foo (y);
Console.WriteLine (y==null);
Output:
The value of y isn't changed just because x is set to null. Remember though that the value of a reference type variable is the reference - if two reference type variables refer to the same object, then changes to the data in that object will be seen via both variables. For example:
void Foo (StringBuilder x)
{
x.Append (" world");
}
...
StringBuilder y = new StringBuilder();
y.Append ("hello");
Foo (y);
Console.WriteLine (y);
Output:
After calling Foo, the StringBuilder object that y refers to contains "hello world", as in Foo the data " world" was appended to that object via the reference held in x.
Now consider what happens when value types are passed by value. As I said before, the value of a value type variable is the data itself. Using the previous definition of the struct IntHolder, let's write some code similar to the above:
void Foo (IntHolder x)
{
x.i=10;
}
...
IntHolder y = new IntHolder();
y.i=5;
Foo (y);
Console.WriteLine (y.i);
Output:
When Foo is called, x starts off as a struct with value i=5. Its i value is then changed to 10. Foo knows nothing about the variable y, and after the method completes, the value in y will be exactly the same as it was before (i.e. 5).
As we did earlier, check that you understand what would happen if IntHolder was declared as a class instead of a struct. You should understand why y.i would be 10 after calling Foo in that case.
Reference Parameters
Reference parameters don't pass the values of the variables used in the function member invocation - they use the variables themselves. Rather than creating a new storage location for the variable in the function member declaration, the same storage location is used, so the value of the variable in the function member and the value of the reference parameter will always be the same. Reference parameters need the ref modifier as part of both the declaration and the invocation - that means it's always clear when you're passing something by reference. Let's look at our previous examples, just changing the parameter to be a reference parameter:
void Foo (ref StringBuilder x)
{
x = null;
}
...
StringBuilder y = new StringBuilder();
y.Append ("hello");
Foo (ref y);
Console.WriteLine (y==null);
Output:
Here, because a reference to y is passed rather than its value, changes to the value of parameter x are immediately reflected in y. In the above example, y ends up being null. Compare this with the result of the same code without the ref modifiers.
Now consider the struct code we had earlier, but using reference parameters:
void Foo (ref IntHolder x)
{
x.i=10;
}
...
IntHolder y = new IntHolder();
y.i=5;
Foo (ref y);
Console.WriteLine (y.i);
Output:
The two variables are sharing a storage location, so changes to x are also visible through y, so y.i has the value 10 at the end of this code.
Sidenote: what is the difference between passing a value object by reference and a reference object by value?
You may have noticed that the last example, passing a struct by reference, had the same effect in this code as passing a class by value. This doesn't mean that they're the same thing, however. Consider the following code:
void Foo (??? IntHolder x)
{
x = new IntHolder();
}
...
IntHolder y = new IntHolder();
y.i=5;
Foo (??? y);
In the case where IntHolder is a struct (i.e. a value type) and the parameter is a reference parameter (i.e. replace ??? with ref above), y ends up being a new IntHolder value - i.e. y.i is 0. In the case where IntHolder is a class (i.e. a reference type) and the parameter is a value parameter (i.e. remove ??? above), the value of y isn't changed - it's a reference to the same object it was before the function member call. This difference is absolutely crucial to understanding parameter passing in C#, and is why I believe it is highly confusing to say that objects are passed by reference by default instead of the correct statement that object references are passed by value by default.
Output Parameters & Parameter Arrays
Output parameters
Like reference parameters, output parameters don't create a new storage location, but use the storage location of the variable specified on the invocation. Output parameters need the out modifier as part of both the declaration and the invocation - that means it's always clear when you're passing something as an output parameter.
Output parameters are very similar to reference parameters. The only differences are:
- The variable specified on the invocation doesn't need to have been assigned a value before it is passed to the function member. If the function member completes normally, the variable is considered to be assigned afterwards (so you can then "read" it).
- The parameter is considered initially unassigned (in other words, you must assign it a value before you can "read" it in the function member).
- The parameter must be assigned a value before the function member completes normally.
Here is some example code showing this, with an int parameter (int is a value type, but if you understood reference parameters properly, you should be able to see what the behaviour for reference types is):
void Foo (out int x)
{
// Can't read x here - it's considered unassigned
// Assignment - this must happen before the method can complete normally
x = 10;
// The value of x can now be read:
int a = x;
}
...
// Declare a variable but don't assign a value to it
int y;
// Pass it in as an output parameter, even though its value is unassigned
Foo (out y);
// It's now assigned a value, so we can write it out:
Console.WriteLine (y);
Output:
Parameter arrays
Parameter arrays allow a variable number of arguments to be passed into a function member. The definition of the parameter has to include the params modifier, but the use of the parameter has no such keyword. A parameter array has to come at the end of the list of parameters, and must be a single-dimensional array. When using the function member, any number of parameters (including none) may appear in the invocation, so long as the parameters are each compatible with the type of the parameter array. Alternatively, a single array may be passed, in which case the parameter acts just as a normal value parameter. For example:
void ShowNumbers (params int[] numbers)
{
foreach (int x in numbers)
{
Console.Write (x+" ");
}
Console.WriteLine();
}
...
int[] x = {1, 2, 3};
ShowNumbers (x);
ShowNumbers (4, 5);
Output:
In the first invocation, the variable x is passed by value, as it's just an array. In the second invocation, a new array of ints is created containing the two values specified, and a reference to this array is passed.
Mini-glossary
Some informal definitions and summaries of terms:
- Function member
- A function member is a method, property, event, indexer, user-defined operator, instance constructor, static constructor, or destructor.
- Output parameter
- A parameter very similar to a reference parameter, but with different definite assignment rules.
- Reference parameter (pass-by-reference semantics)
- A parameter which shares the storage location of the variable used in the function member invocation. As they share the same storage location, they always have the same value (so changing the parameter value changes the invocation variable value).
- Reference type
- Type where the value of a variable/expression of that type is a reference to an object rather than the object itself.
- Storage location
- A portion of memory holding the value of a variable.
- Value parameter (the default semantics, which are pass-by-value)
- A value parameter that has its own storage location, and thus its own value. The initial value is the value of the expression used in the function member invocation.
- Value type
- Type where the value of a variable/expression of that type is the object data itself.
- Variable
- Name associated with a storage location and type. (Usually a single variable is associated with a storage location. The exceptions are for reference and output parameters.)