Crossed ladders
Time Limit:1000MS Memory Limit:65536K
Total Submit:1837 Accepted:605
Description
A narrow street is lined with tall buildings. An x foot long ladder is rested at the base of the building on the right side of the street and leans on the building on the left side. A y foot long ladder is rested at the base of the building on the left side of the street and leans on the building on the right side. The point where the two ladders cross is exactly c feet from the ground. How wide is the street?
Input
Each line of input contains three positive floating point numbers giving the values of x, y, and c.
Output
For each line of input, output one line with a floating point number giving the width of the street in feet, with three decimal digits in the fraction.
Sample Input
30 40 10
12.619429 8.163332 3
10 10 3
10 10 1
Sample Output
26.033
7.000
8.000
9.798
Source
The UofA Local 2000.10.14
My Code:
#include
<
iostream
>
#include
<
algorithm
>
#include
<
cmath
>
#include
<
iomanip
>
using
namespace
std;
![](/Images/OutliningIndicators/None.gif)
void
round(
double
x,
double
y,
double
h)
![](/Images/OutliningIndicators/ExpandedBlockStart.gif)
{
double
s1, s2, s;
double
t, beg, end;
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
if
(x
==
y)
{
s
=
sqrt(x
*
x
-
4
*
h
*
h);
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
}
else
{
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
if
(y
<
x)
{
swap(x, y);
}
beg
=
0
;
end
=
x;
s
=
(beg
+
end)
/
2
;
t
=
1
/
sqrt(x
*
x
-
s
*
s)
+
1
/
sqrt(y
*
y
-
s
*
s);
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
while
(fabs(t
-
1
/
h)
>
0.000000001
)
{
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
if
(t
<
1
/
h)
{
beg
=
s;
s
=
(beg
+
end)
/
2
;
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
}
else
if
(t
>
1
/
h)
{
end
=
s;
s
=
(beg
+
end)
/
2
;
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
}
else
{
break
;
}
t
=
1
/
sqrt(x
*
x
-
s
*
s)
+
1
/
sqrt(y
*
y
-
s
*
s);
}
}
cout
<<
setiosflags(ios::
fixed
)
<<
setprecision(
3
)
<<
s
<<
endl;
}
int
main()
![](/Images/OutliningIndicators/ExpandedBlockStart.gif)
{
double
x, y, h;
![](/Images/OutliningIndicators/ExpandedSubBlockStart.gif)
while
(cin
>>
x
>>
y
>>
h)
{
round(x, y, h);
}
return
0
;
}
posted on 2006-05-08 21:24
豪 阅读(709)
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