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C/C++/STL/Algorithm/D3D
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匈牙利算法

Posted on 2009-08-28 10:35 reiks 阅读(597) 评论(0)  编辑 收藏 引用 所属分类: 算法与数据结构
#include<iostream>
bool map[102][302],use[302];
int link[302],n,m;
bool dfs(int);
int main()
{
    
int t,v,i,j,x,num;
    scanf(
"%d",&t);
    
while (t--)
    
{
        scanf(
"%d%d",&n,&m);
        i
=1;
        
while (i<=n)
        
{
            j
=1;
            
while (j<=m)
                map[i][j
++]=0;
            i
++;
        }


        
// m ->人  n ->课程
        i=1;
        
while (i<=m)
            link[i
++= -1;
        i
=1;

        
while (i<=n)
        
{
            scanf(
"%d",&v);
            j
=0;
            
while (j<v)
            
{
                scanf(
"%d",&x);
                map[i][x]
=1;
                j
++;
            }

            i
++;
        }

        num
=0;
        i
=1;
        
while (i<=n)
        
{
            j
=1;
            
while (j<=m)
                use[j
++]=0;
            
if (dfs(i))
                num
++;
            i
++;
        }

        
if (num==n)
            printf(
"YES\n");
        
else
            printf(
"NO\n");
    }

    
return 0;
}


bool dfs(int x)
{
    
int i,j;
    i
=1;
    
while (i<=m)
    
{
        
if (use[i]==0&&map[x][i])
        
{
            use[i]
=1;
            j
=link[i];
            link[i]
=x;
            
if (j==-1||dfs(j))
            
{
                
return true;
            }

            link[i]
=j;
        }

        i
++;
    }

    
return false;
}

============================================

#include 
<memory.h>
#include 
<stdio.h>
//分别定义左右最大元素
#define LEFT_MAX 501
#define RIGHT_MAX 501

bool useif[RIGHT_MAX];
//link[]记录与右边元素连接的元素,-1表示没有连接
int link[RIGHT_MAX];

int left_num,right_num;

bool array[LEFT_MAX][RIGHT_MAX];

bool can(int t)
{
    
int i;
    
    
for(i=0;i<right_num;i++)
    
{
        
if(!useif[i]&&array[t][i])
        
{
            useif[i]
=true;
            
if(link[i]==-1||can(link[i]))
            
{
                link[i]
=t;
                
return true;
            }

        }


    }

    
return false;
}


int main()
{
    
int i,k,num,temp,num_of_this;
    
char c;
    
//scanf("%d\n",&count);
    
//for(j=0;j<count;j++)
    while(scanf("%d",&left_num)!=-1)
    
{
        right_num
=left_num;
        
//link??-1
        memset(link,0xFF,sizeof(link));
        memset(array,
0,sizeof(array));
        memset(useif,
0,sizeof(useif));
        
        num
=0;
        
        
for(i=0;i<left_num;i++)
        
{
            scanf(
"%d%c%c%c%d%c",&temp,&c,&c,&c,&num_of_this,&c);
            
for(k=0;k<num_of_this;k++)
            
{
                scanf(
"%d",&temp);
                array[i][temp]
=true;
            }

        }

        
//匹配,num为结果
        for(i=0;i<left_num;i++)
        
{
            memset(useif,
0,sizeof(useif));
            
if(can(i))
                num
++;
        }


        
        printf(
"%d\n",left_num-num/2);
        
    }

    
return 1;
}
 

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