Sephiroth's boring days!!!

Love just for you.

区间类动态规划-数字游戏

题目网上都可以找到。

注意初始化s[i][j]的时候要加上100000而不是10!!!我傻叉子了= =

  1: #include <stdio.h>
  2: #define MAXINT 10000000
  3: #define maxn 200
  4: 
  5: int f[maxn][maxn][maxn][2];//0 max|||| 1 min
  6: int s[maxn][maxn];
  7: int a[maxn];
  8: int n,m;
  9: int maxans,minans=MAXINT;
 10: 
 11: void find(int x,int y,int t)
 12: {
 13:     if (f[x][y][t][0]) return;
 14:     if (t==1)
 15:     {
 16:         f[x][y][1][0]=f[x][y][1][1]=s[x][y];
 17:         return;
 18:     }
 19:     for (int k=x+t-1-1;k<y;++k)
 20:     {
 21:         find(x,k,t-1);
 22:         if (f[x][k][t-1][1]*s[k+1][y]<f[x][y][t][1]) f[x][y][t][1]=f[x][k][t-1][1]*s[k+1][y];
 23:         if (f[x][k][t-1][0]*s[k+1][y]>f[x][y][t][0]) f[x][y][t][0]=f[x][k][t-1][0]*s[k+1][y];
 24:     }
 25: }
 26: 
 27: int main()
 28: {
 29:     freopen("game.in","r",stdin);
 30:     freopen("game.out","w",stdout);
 31:     
 32:     scanf("%d%d",&n,&m);
 33:     for (int i=1;i<=n;++i)
 34:     {
 35:         scanf("%d",&a[i]);
 36:         a[i+n]=a[i];
 37:     }
 38:     for (int i=1;i<=2*n;++i)
 39:         for (int j=i;j<=2*n;++j)
 40:             for (int k=1;k<=m;++k)
 41:                 f[i][j][k][1]=MAXINT;
 42:     for (int i=1;i<=2*n;++i)
 43:         for (int j=i;j<=2*n;++j)
 44:             s[i][j]=(s[i][j-1]+a[j]+100000)%10;
 45:     for (int i=1;i<=n;++i) find(i,i+n-1,m);
 46:     for (int i=1;i<=n;++i)
 47:     {
 48:         if (f[i][i+n-1][m][0]>maxans) maxans=f[i][i+n-1][m][0];
 49:         if (f[i][i+n-1][m][1]<minans) minans=f[i][i+n-1][m][1];
 50:     }
 51:     printf("%d\n%d\n",minans,maxans);
 52:     return 0;
 53: }
 54: 

posted on 2010-09-01 21:40 Sephiroth Lee 阅读(324) 评论(0)  编辑 收藏 引用 所属分类: 信息奥赛


只有注册用户登录后才能发表评论。
网站导航: 博客园   IT新闻   BlogJava   博问   Chat2DB   管理


free counters