Posted on 2010-12-06 22:17
Sivan 阅读(501)
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C/C++
看了《金山卫士代码批评》一文,发现了一些自己存在的问题。
1.const使用
1.1 const修饰参数
1)参数为输出参数,不论什么数据类型,不论什么参数传递方式,都不加const。
2)输入参数“指针传递”,加const防止改动指针。
3)输入参数“值传递”,内置类型,参数不加const修饰,非内置类型,常使用引用传递,如果不想改变参数,加const修饰,如void Fun(const A & a)
1.2 const修饰函数返回值
1)返回值“指针传递”,加const修饰,函数返回值内容不能被修改,返回值只能赋给加const修饰的同类型指针。
2)返回值“值传递”,加const修饰无意义。
3)返回值引用传递,一般只出现在类的赋值函数中,实现链式表达。
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class A
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{
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A & operator = (const A &other); // 赋值函数
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}
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1.3 const成员函数
任何不会修改数据成员的函数都应该声明为const类型。
规则:
1)const对象只能访问const成员函数,而非const对象可以访问任意的成员函数,包括const成员函数。
2)const对象的成员是不可修改的,而const对象通过指针维护的对象却是可以修改的。
3)const成员函数不可以修改对象的数据,不管对象是否具有const性质。
4)mutable修饰的数据成员,对通过任何手段都可以修改,const成员函数也可以修改。
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class A
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{
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public:
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A(int i):m_nVal(i)
{m_pVal = new int();}
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void Print()
{cout<<m_nVal<<" "<<*m_pVal<<endl;}
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void Print() const
{cout<<"const print:"<<m_nVal<<" "<<*m_pVal<<endl;}
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int* m_pVal;
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int m_nVal;
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};
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int main()
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{
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const A a(1);
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a.Print(); // 规则1,const对象只能防伪const成员函数
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//a.m_nVal = 2; // 规则2,const对象的成员不可修改
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*(a.m_pVal) = 3; // 规则2,const对象通过指针维护的对象可以修改
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return 0;
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}
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2.表驱动
以前使用过表驱动方法,但是并不知道这就是表驱动。
表驱动方法是一种可以在表中查找信息,而不必使用很多逻辑语句(if,switch case)来找出的方法。
2.1 逻辑性不强
例:
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void GetWeekDays(string & strDay, int iDay)
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{
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if(1 == iDay)
{strDay = "Monday";}
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else if(2 == iDay)
{strDay = "Tuesday";}
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else if(3 == iDay)
{strDay = "Wednesday";}
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else if(4 == iDay)
{strDay = "Thursday";}
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else if(5 == iDay)
{strDay = "Friday";}
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else if(6 == iDay)
{strDay = "Saturday";}
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else if(7 == iDay)
{strDay = "Sunday";}
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return;
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}
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表驱动方法
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static string strWeekDays[] =
{"Monday","Tuesday","Wednesday",
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"Thursday","Friday","Saturday","Sunday"};
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void GetWeekDays2(string & strDay, int iDay)
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{
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strDay = strWeekDays[iDay-1];
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}
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2.2 函数指针在表驱动方法中应用
不同分支调用不同的函数
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void FunA(string strType)
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{
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if (strType == "1")
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{
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DoFun1();
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}
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if (strType == "2")
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{
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DoFun1();
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}
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if (strType == "3")
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{
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DoFun1();
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}
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if (strType == "4")
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{
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DoFun1();
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}
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if (strType == "5")
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{
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DoFun1();
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}
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if (strType == "6")
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{
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DoFun1();
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}
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if (strType == "7")
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{
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DoFun1();
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}
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}
表驱动方法
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typedef struct
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{
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string strType;
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void (*Fun)(void);
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}DoTable;
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static const DoTable Table[]=
{
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{"1",DoFun1},
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{"2",DoFun2},
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{"3",DoFun3},
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{"4",DoFun4},
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{"5",DoFun5},
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{"6",DoFun6},
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{"7",DoFun7}
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}
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}
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void FunA(string strType)
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{
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int nCount = sizeof(Table)/sizeof(Table[0]);
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for (int i=0; i!=nCount; ++i)
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{
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if (Table[i] == strType)
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{
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(*Table[i].Fun)();
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}
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}
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}
参考:
1.http://www.cnblogs.com/Fancyboy2004/archive/2008/12/23/1360810.html
2.http://www.cnblogs.com/MichaelPeng/archive/2010/12/02/1893999.html?page=1#pagedcomment
3.http://baike.baidu.com/view/3707325.htm