POJ 1002 487-3279 字符串处理 - Vontroy - C++博客

POJ 1002 487-3279 字符串处理

#include <iostream>

#include <string>

#include <algorithm>

#include <cstdio>

const int maxn = 20000;

const int MAXN = 100000+10;

using std :: string;

using std :: cout;

using std :: endl;

int main()

{

string ans[MAXN];

char tel[maxn];

char store[maxn];

int n;

bool ok;

while(~ scanf("%d",&n))

{

ok = false;

int count = 0;

while(n--)

{

scanf("%s",tel);

int j;

for(int i = 0,j = 0; tel[i] != '\0'; i++)

{

if(tel[i]-'0'>=0&&tel[i]-'0'<=9)

store[j++] = tel[i];

else if(tel[i] != '-' && j != 3 )

{

//ans[count]+='2';

if(tel[i]=='A'||tel[i]=='B'||tel[i]=='C')

store[j++] = '2';

else if(tel[i]=='D'||tel[i]=='E'||tel[i]=='F')

store[j++] = '3';

else if(tel[i]=='G'||tel[i]=='H'||tel[i]=='I')

store[j++] = '4';

else if(tel[i]=='J'||tel[i]=='K'||tel[i]=='L')

store[j++] = '5';

else if(tel[i]=='M'||tel[i]=='N'||tel[i]=='O')

store[j++] = '6';

else if(tel[i]=='P'||tel[i]=='R'||tel[i]=='S')

store[j++] = '7';

else if(tel[i]=='T'||tel[i]=='U'||tel[i]=='V')

store[j++] = '8';

else if(tel[i]=='W'||tel[i]=='X'||tel[i]=='Y')

store[j++] = '9';

}

if( j==3 ) store[j++]='-';

}

ans[count++] = store;

}

std :: sort(ans,ans+count);

int ans_count;

for(int i = 0; i < count; i++)

{

ans_count = 1;

for(int j = i + 1; j < count; j++)

{

if(ans[j]==ans[i]) ans_count++;

else break;

}

if(ans_count > 1)

{

ok = true;

cout << ans[i] << " " << ans_count << endl;

i+=(ans_count-1);

}

}

if(!ok) cout << "No duplicates." << endl;

//for(int i = 0; i <count; i++)

//std :: cout << ans[i] << std :: endl;

}

return 0;

}

posted on 2010-10-02 19:21 Vontroy 阅读(295) 评论(0) 编辑收藏引用所属分类: 字符串、POJ

只有注册用户登录后才能发表评论。
【推荐】100%开源！大型工业跨平台软件C++源码提供，建模，组态！

相关文章: 字典树(Trie树) HDU 2734 Quicksum 简单字符串处理 POJ 1007 DNA Sorting 字符串处理\|稳定排序 POJ 1002 487-3279 字符串处理

网站导航: 博客园 IT新闻 BlogJava 博问 Chat2DB 管理