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Here is a simple implementation to convert string to 0x string.
Better one is expected ......
 1 #include <assert.h>
 2 /*
 3  * convert string to 0x string.
 4  * 
 5  * const char* ipt input string.
 6  * char* opt output 0x string.
 7  */
 8 void str2Xstr(const char* ipt, char* opt)
 9 {
10     assert(ipt != NULL && opt != NULL);
11     assert(sizeof(char== 1);
12 
13     /* add prefix 0x into opt */
14     *opt++ = '0';
15     *opt++ = 'x';
16 
17     char* bak = opt;
18     while(*ipt != '\0') {
19         /* get the char and cast it to int */
20         char cha = *ipt++;
21         unsigned short tmp = cha;
22         /* assert sizeof char is 1 (8bits) */
23         tmp <<= 8;
24         tmp >>= 12;
25         if(tmp >= 10*opt++ = tmp-10+'A';
26         else *opt++ = tmp+'0';
27 
28         tmp = cha;
29         tmp <<= 12;
30         tmp >>= 12;
31         if(tmp >= 10*opt++ = tmp-10+'A';
32         else *opt++ = tmp+'0';
33     }
34     /* terminate string */
35     *opt = 0;
36 }
37 
38 int main()
39 {
40     char opt[64= {0};
41     str2Xstr("2009-09", opt);
42     puts(opt); /* 0x323030392D3039 */
43     getchar();
44     return 0;
45 }


Using & operation is a better way:
 1 /*
 2  * convert string to 0x string.
 3  * 
 4  * const char* ipt input string.
 5  * char* opt output 0x string.
 6  */
 7 void str2Xstr(const char* ipt, char* opt)
 8 {
 9     assert(ipt != NULL && opt != NULL);
10     assert(sizeof(char== 1);
11 
12     /* add prefix 0x into opt */
13     *opt++ = '0';
14     *opt++ = 'x';
15 
16     char* bak = opt;
17     while(*ipt != '\0') {
18         /* get the char and cast it to int */
19         char cha = *ipt++;
20         unsigned char tmp = cha;
21         /* assert sizeof char is 1 (8bits) */
22         tmp &= '\xF0';
23         tmp >>= 4;
24         *opt++ = tmp >= 10 ? tmp-10+'A' : tmp+'0';
25 
26         tmp = cha;
27         tmp &= '\x0F';
28         *opt++ = tmp >= 10 ? tmp-10+'A' : tmp+'0';
29     }
30     /* terminate string and turn back one step */
31     *opt-- = 0;
32 }

posted on 2010-10-21 11:40 JonsenElizee 阅读(423) 评论(0)  编辑 收藏 引用

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