Posted on 2014-01-11 02:51
Uriel 阅读(132)
评论(0) 编辑 收藏 引用 所属分类:
LeetCode
一天遇到两次一样的题简直...要是能在之前一天能做一下这题多好，就不至于当时题目问了几遍才明白...
给出逆波兰式，求算式的值，模拟栈，乘除的时候注意出栈顺序！和算式的操作数顺序相反！下午就死在这上面了...
1 class Solution {
2 public:
3 int evalRPN(vector<string> &tokens) {
4 int stk[1010], k = 0;
5 for(int i = 0; i < tokens.size(); ++i) {
6 if(tokens[i] == "+") {
7 int a = stk[k - 1], b = stk[k - 2];
8 k -= 2;
9 stk[k++] = a + b;
10 }
11 else if(tokens[i] == "-") {
12 int a = stk[k - 1], b = stk[k - 2];
13 k -= 2;
14 stk[k++] = b - a;
15 }
16 else if(tokens[i] == "*") {
17 int a = stk[k - 1], b = stk[k - 2];
18 k -= 2;
19 stk[k++] = b * a;
20 }
21 else if(tokens[i] == "/") {
22 int a = stk[k - 1], b = stk[k - 2];
23 k -= 2;
24 stk[k++] = b / a;
25 }
26 else {
27 stk[k++] = atoi(tokens[i].c_str());
28 }
29 }
30 return stk[0];
31 }
32 };