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Posted on 2009-09-25 23:28 Uriel 阅读(610) 评论(0) 编辑 收藏 引用 所属分类: POJ 、 计算几何
WA无数次啊。。。看了Discuss之后又WA数次才过。。。 1. n<=5,一律输出NO 2. 所有点共线,NO 3. 凸包上每条边上至少有三点,否则NO
 /**//*Problem: 1228 User: Uriel
Memory: 616K Time: 0MS
Language: G++ Result: Accepted */
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#include <math.h>
#include <stdio.h>
#include <stdlib.h>
#include <memory.h>
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#define eps 1e-8
#define MAXN 1005
#define zero(x) (((x)>0?(x):-(x))<eps)
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struct point
  {
double x,y;
};
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point P[MAXN],convex[MAXN];
int t,n,i,j,flag[MAXN],k;
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//计算cross product (P1-P0)x(P2-P0)
 double xmult(point p1,point p2,point p0) {
return (p1.x-p0.x)*(p2.y-p0.y)-(p2.x-p0.x)*(p1.y-p0.y);
}
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//graham算法顺时针构造包含所有共线点的凸包,O(nlogn)
point p1,p2;
 int graham_cp(const void* a,const void* b) {
double ret=xmult(*((point*)a),*((point*)b),p1);
return zero(ret)?(xmult(*((point*)a),*((point*)b),p2)>0?1:-1):(ret>0?1:-1);
}
 void _graham(int n,point* p,int& s,point* ch) {
int i,k=0;
for (p1=p2=p[0],i=1;i<n;p2.x+=p[i].x,p2.y+=p[i].y,i++)
if (p1.y-p[i].y>eps||(zero(p1.y-p[i].y)&&p1.x>p[i].x))
p1=p[k=i];
p2.x/=n,p2.y/=n;
p[k]=p[0],p[0]=p1;
qsort(p+1,n-1,sizeof(point),graham_cp);
for (ch[0]=p[0],ch[1]=p[1],ch[2]=p[2],s=i=3;i<n;ch[s++]=p[i++])
for (;s>2&&xmult(ch[s-2],p[i],ch[s-1])<-eps;s--);
}
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//构造凸包接口函数,传入原始点集大小n,点集p(p原有顺序被打乱!)
//返回凸包大小,凸包的点在convex中
//参数maxsize为1包含共线点,为0不包含共线点,缺省为1
//参数clockwise为1顺时针构造,为0逆时针构造,缺省为1
//在输入仅有若干共线点时算法不稳定,可能有此类情况请另行处理!
//不能去掉点集中重合的点
 int graham(int n,point* p,point* convex,int maxsize=0,int dir=1) {
point* temp=new point[n];
int s,i;
_graham(n,p,s,temp);
for (convex[0]=temp[0],n=1,i=(dir?1:(s-1));dir?(i<s):i;i+=(dir?1:-1))
if (maxsize||!zero(xmult(temp[i-1],temp[i],temp[(i+1)%s])))
convex[n++]=temp[i];
delete []temp;
return n;
}
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//判点是否在线段上,包括端点
int dot_online_in(point p,point l1,point l2)
  {
return zero(xmult(p,l1,l2))&&(l1.x-p.x)*(l2.x-p.x)<eps&&(l1.y-p.y)*(l2.y-p.y)<eps;
}
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int main()
  {
scanf("%d",&t);
while(t--)
 {
scanf("%d",&n);
for(i=0;i<n;i++)
 {
scanf("%lf %lf",&P[i].x,&P[i].y);
}
if(n<=5)
 {
printf("NO\n");
continue;
}
k=0;
for(i=1;i<n-1;i++)
 {
if(xmult(P[0],P[n-1],P[i])!=0)
 {
k=1;
break;
}
}
if(!k)
 {
printf("NO\n");
continue;
}
int M=graham(n,P,convex,0,1);
if(M==n)
 {
printf("NO\n");
continue;
}
memset(flag,0,sizeof(flag));
for(i=0;i<n;i++)
 {
for(j=0;j<M-1;j++)
 {
if(dot_online_in(P[i],convex[j],convex[j+1]))
 {
flag[j]++;
}
}
if(dot_online_in(P[i],convex[M-1],convex[0]))
 {
flag[M-1]++;
}
}
k=0;
for(i=0;i<M;i++)
 {
if(flag[i]<3)
 {
k=1;
break;
}
}
if(!k)
 {
printf("YES\n");
}
else
 {
printf("NO\n");
}
}
system("PAUSE");
return 0;
}
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