重温了下 背包九讲 不仅发现了其中的一些错误 也发现了这篇文章的局限性,例如这个题。。。做完之后 我对背包的概念又模糊了。。。
#include<iostream>
using namespace std;
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int dp[10001];
int w[10001];
int v[10001];
int main()
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{
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int t;
int e,f;
int n;
int ww;
scanf("%d",&t);
int i,j,k;
for(i=1;i<=t;i++)
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{
scanf("%d%d",&e,&f);
ww=f-e;
scanf("%d",&n);
for(j=1;j<=n;j++)
scanf("%d%d",&v[j],&w[j]);
memset(dp,-1,sizeof(dp));
dp[0]=0;
for(j=1;j<=n;j++)
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{
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for(k=0;k<=ww-w[j];k++)
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{
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if(dp[k]!=-1)
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{
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if(dp[k+w[j]]==-1)
dp[k+w[j]]=dp[k]+v[j];
else
dp[k+w[j]]=min(dp[k+w[j]],dp[k]+v[j]);
}
}
}
if(dp[ww]==-1)
printf("This is impossible.\n");
else
printf("The minimum amount of money in the piggy-bank is %d.\n",dp[ww]);
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}
return 0;
}
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