下面有个函数,用于将6个字节的字符数组‘转换’到12字节。例如:
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src[6] =
{ 0x12, 0x34, 0x56, 0x78, 0x9a, 0xbc }
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dst[12] =
{ '1','2','3','4','5','6','7','8','9','a','b','c' }
因为目标是字符串风格,为了显示需要,dst实际使用的是13字节长度数组,如下:
unsigned char dst[13];
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makeId(dst, src);
函数如下,麻烦找下Bug。
void ISLUtil::makeId(unsigned char* id, const unsigned char* ptr)
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{
int i = 0;
while(i < 6)
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{
unsigned char t = *ptr >> 4;
if(t >= 0 && t <= 9)
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{
*id = t + '0';
}
else if(t >= 0x0a && t <= 0x0f)
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{
*id = t + 'a';
}
else
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{
*id = 0;
}
t = (*ptr & 0x0F);
++ id;
if(t >= 0 && t <= 9)
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{
*id = t + '0';
}
else if(t >= 0x0a && t <= 0x0f)
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{
*id = t + 'a';
}
else
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{
*id = 0;
}
++ ptr;
++ id;
++ i;
}
id[12] = '\0';
}
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Y的,白痴的错误搞了我两天。。。。