心如止水
Je n'ai pas le temps
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从string中寻找"P="、"U="、"I=",然后记录P、U、I的值,使用istringstream比较方便。
以下是我的代码:
#include<iostream>
#include
<sstream>
#include
<string>
#include
<cstdio>
using namespace std;

int main()
{
    
/*
    freopen("data.in","r",stdin);
    freopen("data.out","w",stdout);
    //
*/

    
int T;
    cin
>>T;getchar();
    
for(int case_num=1;case_num<=T;case_num++)
    {
        
string line;
        getline(cin,line);
        
double P(-1.0),U(-1.0),I(-1.0);
        istringstream sin(line);
        
char ch;
        
while(sin>>ch)
        {
            
if(ch=='P')
            {
                
char t;
                sin
>>t;
                
if(t!='=')
                    
continue;
                sin
>>P;
                sin
>>t;
                
if(t=='m')
                    P
/=1000;
                
else if(t=='k')
                    P
*=1000;
                
else if(t=='M')
                    P
*=1000000;
            }
            
else if(ch=='U')
            {
                
char t;
                sin
>>t;
                
if(t!='=')
                    
continue;
                sin
>>U;
                sin
>>t;
                
if(t=='m')
                    U
/=1000;
                
else if(t=='k')
                    U
*=1000;
                
else if(t=='M')
                    U
*=1000000;
            }
            
else if(ch=='I')
            {
                
char t;
                sin
>>t;
                
if(t!='=')
                    
continue;
                sin
>>I;
                sin
>>t;
                
if(t=='m')
                    I
/=1000;
                
else if(t=='k')
                    I
*=1000;
                
else if(t=='M')
                    I
*=1000000;
            }
        }

        cout
<<"Problem #"<<case_num<<endl;
        
if(P==-1.0)
            printf(
"P=%.2fW\n",U*I);
        
else if(U==-1.0)
            printf(
"U=%.2fV\n",P/I);
        
else
            printf(
"I=%.2fA\n",P/U);
        printf(
"\n");
    }

    
return 0;
}
posted on 2011-04-07 12:53 lee1r 阅读(686) 评论(0)  编辑 收藏 引用 所属分类: 题目分类:字符串处理

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