#include
<
iostream
>
using
namespace
std;
int
N,k;
int
ch1[
110
],ch2[
110
],val[
110
];
int
f[
110
][
110
];
int
vis[
110
];
inline
int
max(
int
x,
int
y){
return
x
>
y
?
x:y;
}
void
treedp(
int
x){
int
root,c1
=
0
,c2;
vis[x]
=
1
;
for
(
int
i
=
1
;i
<
N;
++
i)
if
(ch1[i]
==
x
||
ch2[i]
==
x){
root
=
ch1[i]
+
ch2[i]
-
x;
if
(vis[root])
f[x][
1
]
=
val[i];
else
{
if
(
!
c1) c1
=
root;
else
c2
=
root;
treedp(root);
}
}
if
(c1)
for
(
int
i
=
1
;i
<=
k;
++
i)
for
(
int
j
=
0
;j
<
i;
++
j)
f[x][i]
=
max(f[x][i],f[x][
1
]
+
f[c1][j]
+
f[c2][i
-
1
-
j]);
}
int
main()
{
cin
>>
N
>>
k;
k
++
;
for
(
int
i
=
1
;i
<
N;
++
i)
cin
>>
ch1[i]
>>
ch2[i]
>>
val[i];
memset(f,
0
,
sizeof
(f));
memset(vis,
0
,
sizeof
(vis));
treedp(
1
);
cout
<<
f[
1
][k]
<<
endl;
return
0
;
}
posted on 2009-05-30 09:46
xfstart07 阅读(199)
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